-72x^2+63x=0

Solution for -72x^2+63x=0 equation:

-72x^2+63x=0

a = -72; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·(-72)·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*-72}=\frac{-126}{-144}
=7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*-72}=\frac{0}{-144}
=0
$